Convolution in the time domain becomes multiplication in the frequency domain.
\(H(e^{j\omega})\) is the frequency response of the LTI system, which is the DTFT of the impulse response \(h[n]\).
Important
This property is a cornerstone of LTI system analysis, allowing us to analyze system behavior in the frequency domain, which is often much simpler.
Why is it so useful?
Simplifies Analysis: Converts complex convolution into algebraic multiplication.
System Understanding:\(H(e^{j\omega})\) directly shows how a system affects different frequencies.
Magnitude Response \(|H(e^{j\omega})|\): Gain at each frequency.
Phase Response \(\operatorname{Arg}\{H(e^{j\omega})\}\): Phase shift at each frequency.
Filter Design: Allows direct specification of desired frequency characteristics (e.g., passband, stopband) to design filters.
Eigenfunction Interpretation: Complex exponentials \(e^{j\omega n}\) are eigenfunctions of LTI systems. The frequency response \(H(e^{j\omega})\) is the eigenvalue for \(e^{j\omega n}\).
Example 5.11: Time Shift System
Consider an LTI system with impulse response:
\[
h[n]=\delta\left[n-n_{0}\right]
\]
This system simply delays the input by \(n_0\) samples: \(y[n] = x[n-n_0]\).
1. Find the frequency response \(H(e^{j\omega})\):
This is consistent with the time-shifting property: \(x[n-n_0] \stackrel{\mathcal{F}}{\longleftrightarrow} e^{-j\omega n_0} X(e^{j\omega})\).
Note
The frequency response \(H(e^{j\omega})=e^{-j\omega n_0}\) has:
Unity magnitude:\(|H(e^{j\omega})|=1\) for all \(\omega\). (No frequency is amplified or attenuated)
Linear phase:\(\operatorname{Arg}\{H(e^{j\omega})\} = -\omega n_0\). (All frequencies are delayed by the same amount, \(n_0\) samples, resulting in a constant group delay).
Example 5.12: Ideal Discrete-Time Lowpass Filter
An ideal lowpass filter has a frequency response \(H(e^{j\omega})\) as shown:
Figure 5.17(a): Ideal lowpass filter frequency response.
We can find its impulse response \(h[n]\) using the inverse DTFT:
3. Find inverse DTFT of \(Y(e^{j\omega})\) using partial fractions:
Case 1: \(\alpha \neq \beta\)\[
Y\left(e^{j \omega}\right)=\frac{A}{1-\alpha e^{-j \omega}}+\frac{B}{1-\beta e^{-j \omega}}
\] where \(A=\frac{\alpha}{\alpha-\beta}\) and \(B=-\frac{\beta}{\alpha-\beta}\). Taking the inverse DTFT (using linearity and Example 5.1): \[
y[n]=\frac{1}{\alpha-\beta}\left[\alpha^{n+1} u[n]-\beta^{n+1} u[n]\right] \quad \text{(Eq. 5.55)}
\]
Case 2: \(\alpha = \beta\)\[
Y\left(e^{j \omega}\right)=\left(\frac{1}{1-\alpha e^{-j \omega}}\right)^{2}
\] Using the differentiation in frequency property (Eq. 5.46) and time-shifting property: \[
y[n]=(n+1) \alpha^{n} u[n] \quad \text{(Eq. 5.58)}
\]
Example 5.14: System Interconnection Analysis
Consider the system shown in Figure 5.18(a).
Figure 5.18(a): System interconnection.
\(H_{lp}(e^{j\omega})\) are ideal lowpass filters with cutoff \(\pi/4\).
The “\(-1\)” blocks multiply by \((-1)^n = e^{j\pi n}\).
The overall frequency response is \(H(e^{j\omega}) = H_{lp}(e^{j(\omega-\pi)}) + H_{lp}(e^{j\omega})\).
Figure 5.18(b): Overall frequency response.
Tip
\(H_{lp}(e^{j(\omega-\pi)})\) is the frequency response of an ideal highpass filter (from Example 5.7). Thus, the overall system creates an ideal bandstop filter, passing low and high frequencies, and stopping frequencies between \(\pi/4\) and \(3\pi/4\).
Stability and Frequency Response
Not all LTI systems have a well-defined frequency response.