Motion, Pressure, and Flow Sensors

Instruments 5.2

Imron Rosyadi

Learning Objectives

By the end of this session, you will be able to:

  1. Relate position, velocity, and acceleration mathematically and explain what an accelerometer actually measures.
  2. Distinguish rectilinear, angular, vibration, and shock motion and match each to appropriate sensor types.
  3. Explain the spring–mass accelerometer principle, including natural frequency and damping effects.
  4. Compare common accelerometer implementations: potentiometric, LVDT, variable‑reluctance, and piezoelectric.
  5. Define pressure, gauge pressure, and head pressure, and convert among common pressure units.
  6. Describe how diaphragms, bellows, Bourdon tubes, and solid‑state sensors convert pressure to electrical signals.
  7. Apply pressure and flow equations to typical design problems (level via pressure, flow via pressure drop, etc.).

Motion: From Position to Acceleration

If an object’s position is \(x(t)\):

  • Velocity: \[v(t) = \frac{dx(t)}{dt} \tag{16}\]

  • Acceleration: \[a(t) = \frac{dv(t)}{dt} = \frac{d^2 x(t)}{dt^2} \tag{17}\]

If we know acceleration \(a(t)\), we can integrate to get:

  • Velocity: \[v(t) = v(0) + \int_0^t a(\tau)\, d\tau \tag{18}\]

  • Position: \[x(t) = x(0) + \int_0^t v(\tau)\, d\tau \tag{19}\]

Tip

An accelerometer measures \(a(t)\), but with integration (usually electronic) we can estimate \(v(t)\) and \(x(t)\).

Units & “g”

  • Proper SI acceleration unit: \(\mathrm{m/s^2}\)
  • Velocity: \(\mathrm{m/s}\)
  • Position: m

Often accelerations are normalized to earth gravity:

  • \(1\ \mathbf{g} \approx 9.8\ \mathrm{m/s^2}\)

So:

  • \(a = 2\ \mathbf{g} \Rightarrow a \approx 19.6\ \mathrm{m/s^2}\)
  • Smartphone accelerometers will read roughly \(+1\ \mathbf{g}\) “down” even sitting still, due to gravity.

Example 11 – Unit Conversion to m/s² and g

An automobile is accelerating away from a stop sign at \(26.4\ \mathrm{ft/s^2}\).

Find the acceleration in:

  1. \(\mathrm{m/s^2}\)
  2. \(\mathbf{g}\)s

Solution

Convert feet to meters:

\[ a = (26.4\ \mathrm{ft/s^2})(12\ \mathrm{in/ft})(2.54\ \mathrm{cm/in})(0.01\ \mathrm{m/cm}) \]

\[ a \approx 8.05\ \mathrm{m/s^2} \]

Express in g’s:

\[ a_{\mathbf{g}} = \frac{8.05\ \mathrm{m/s^2}}{9.8\ \mathrm{m/s^2}/\mathbf{g}} \approx 0.82\ \mathbf{g} \]

Note

That car launch is about \(82\%\) of gravity. Pretty sporty, but still under \(1\ \mathbf{g}\).

Types of Motion & Sensor Needs

Four basic motion categories:

  1. Rectilinear – straight‑line motion; low angular content.
  2. Angular (rotational) – rotation about an axis (e.g., motor shaft).
  3. Vibration – periodic motion about equilibrium, possibly large peak acceleration.
  4. Shock – very large acceleration/deceleration over a very short time.

Sensor Matching

  • Rectilinear:
    • Linear accelerometers, often low‑g range.
  • Angular:
    • Shaft encoders, gyroscopes, rotary potentiometers.
  • Vibration:
    • High‑bandwidth accelerometers (often piezoelectric).
  • Shock:
    • High‑g, high‑frequency accelerometers.

Car crash test – high‑g shock environment

Vibration Motion Model

For simple periodic (harmonic) vibration:

\[ x(t) = x_0 \sin(\omega t) \tag{20} \]

Where:

  • \(x(t)\) = position (m)
  • \(x_0\) = peak displacement from equilibrium (m)
  • \(\omega\) = angular frequency (rad/s)

Vibration about equilibrium at x = 0

Relationship between frequency and angular frequency:

\[ \omega = 2\pi f \tag{21} \]

Vibration: Velocity & Acceleration

Starting with \[x(t) = x_0 \sin(\omega t)\]

Velocity (first derivative):

\[ v(t) = \omega x_0 \cos(\omega t) \tag{22} \]

Acceleration (second derivative):

\[ a(t) = -\omega^2 x_0 \sin(\omega t) \tag{23} \]

  • All three signals are sinusoids at the same frequency.
  • They differ by amplitude and phase.

Peak acceleration:

\[ a_{\text{peak}} = \omega^2 x_0 \tag{24} \]

Important

Peak acceleration rises with \(\omega^2\). Doubling frequency quadruples peak acceleration (for the same displacement).

Example 12 – Vibration Peak Acceleration

A water pipe vibrates at \(f = 10\ \mathrm{Hz}\) with displacement \(x_0 = 0.5\ \mathrm{cm}\).

Find:

  1. Peak acceleration in \(\mathrm{m/s^2}\)
  2. Peak acceleration in \(\mathbf{g}\)

Solution

Compute \(\omega\) and convert \(x_0\):

  • \(\omega = 2\pi f = 20\pi\ \mathrm{rad/s}\)
  • \(x_0 = 0.5\ \mathrm{cm} = 0.005\ \mathrm{m}\)
  1. Peak acceleration:

\[ a_{\text{peak}} = \omega^2 x_0 = (20\pi)^2 (0.005) \approx 19.7\ \mathrm{m/s^2} \]

  1. Express in g’s:

\[ a_{\text{peak}} = \frac{19.7\ \mathrm{m/s^2}}{9.8\ \mathrm{m/s^2/g}} \approx 2.0\ \mathbf{g} \]

Warning

A 2‑g vibration is serious; repeated exposure can damage pipes, valves, and electronics.

Shock Motion

Shock = very large deceleration over a short time.

Typical characteristics:

  • Peak acceleration: often \(> 500\ \mathbf{g}\)
  • Duration: milliseconds (ms) range
  • Occurs in: drops, impacts, collisions

Typical shock acceleration profile

Key quantities:

  • \(a_{\text{peak}}\) – peak acceleration/deceleration
  • \(T_d\) – shock duration
  • Sometimes we use an average shock value based on velocity change and duration.

Example 13 – Average Shock from a Drop

A TV set is dropped from height \(h = 2\ \mathrm{m}\). If the shock duration at impact is \(T_d = 5\ \mathrm{ms}\), find the average shock in g.

Solution

  1. Velocity at impact from \(v^2 = 2 g h\):

\[ v^2 = 2(9.8)(2.0) \Rightarrow v \approx 6.3\ \mathrm{m/s} \]

  1. Average deceleration \(\bar{a}\) over \(T_d\):

\[ \bar{a} = \frac{v}{T_d} = \frac{6.3\ \mathrm{m/s}}{5 \times 10^{-3}\ \mathrm{s}} \approx 1260\ \mathrm{m/s^2} \]

  1. Convert to g’s:

\[ \bar{a} \approx \frac{1260\ \mathrm{m/s^2}}{9.8\ \mathrm{m/s^2/g}} \approx 128\ \mathbf{g} \]

Warning

\(128\ \mathbf{g}\) average shock explains why the TV breaks apart on impact.

Spring–Mass Accelerometer Principle

Core idea: combine Newton’s law and Hooke’s law.

  • Newton: \(F = ma\)
  • Hooke: \(F = k \Delta x\)

Equate forces:

\[ ma = k\Delta x \tag{25} \]

Solve for acceleration:

\[ a = \frac{k}{m} \Delta x \tag{26} \]

So:

  • A test mass (seismic mass) attached to a spring is accelerated.
  • The mass “lags” behind slightly, stretching/compressing the spring by \(\Delta x\).
  • Measure \(\Delta x\) → infer \(a\).

Spring–mass system, no acceleration (left), under acceleration (right)

Natural Frequency & Damping

Any mass–spring system has a natural frequency \(f_N\):

\[ f_N = \frac{1}{2\pi} \sqrt{\frac{k}{m}} \tag{27} \]

And a damped transient response after a disturbance:

\[ X_T(t) = X_0 e^{-\alpha t} \sin(2\pi f_N t) \tag{28} \]

Where:

  • \(X_T(t)\) = transient displacement
  • \(X_0\) = initial peak displacement
  • \(\alpha\) = damping coefficient (s\(^{-1}\))

Damped oscillation of spring–mass system

Note

Near \(f_N\), the system can resonate → large motion and nonlinear response.

Accelerometer Under Vibration

Consider a spring–mass accelerometer mounted on a vibrating table.

  • Table motion: \[x_{\text{table}}(t) = x_0 \sin(\omega t)\]

  • Table acceleration: \[a(t) = -\omega^2 x_0 \sin(\omega t)\]

Using \(ma = k\Delta x\):

\[ \Delta x = -\frac{m x_0}{k}\, \omega^2 \sin(\omega t) \tag{29} \]

Where:

  • \(x_0\) = table vibration amplitude
  • \(\Delta x\) = relative mass motion
  • \(\omega = 2\pi f\) = applied angular frequency

Key idea (ignoring resonance):

  • \(\Delta x \propto \omega^2 x_0\) → response grows with frequency squared.

Frequency Response & Resonance

Frequency response of spring–mass system vs. simple ω² prediction
  1. Actual response vs. ideal \(\omega^2\)

Effect of stops and high-frequency behavior
  1. Saturation by physical stops; high‑frequency displacement behavior

Rules of thumb:

  1. \(f < f_N\):
    • For \(f \lesssim f_N / 2.5\), response approximates Equations (25) and (29).
  2. \(f \gg f_N\):
    • Output becomes essentially a displacement sensor for \(x_0\), almost independent of \(f\).
  3. Near \(f_N\):
    • Large, nonlinear response → avoid using accelerometers near resonance.

Example 14 – Accelerometer Range & Natural Frequency

An accelerometer:

  • Seismic mass: \(m = 0.05\ \mathrm{kg}\)
  • Spring constant: \(k = 3.0 \times 10^3\ \mathrm{N/m}\)
  • Max mass displacement before hitting stops: \(\pm 0.02\ \mathrm{m}\)

Find:

  1. Maximum measurable acceleration in g.
  2. Natural frequency \(f_N\).

Solution

  1. Maximum acceleration (at max \(\Delta x\)):

\[ a = \frac{k}{m} \Delta x = \frac{3.0 \times 10^3}{0.05}(0.02) \approx 1200\ \mathrm{m/s^2} \]

Convert to g’s:

\[ a \approx \frac{1200}{9.8} \approx 122\ \mathbf{g} \]

  1. Natural frequency:

\[ f_N = \frac{1}{2\pi} \sqrt{\frac{k}{m}} = \frac{1}{2\pi} \sqrt{\frac{3.0 \times 10^3}{0.05}} \approx 39\ \mathrm{Hz} \]

Tip

This accelerometer can measure up to about ±122 g, but has a fairly low natural frequency (~39 Hz), so it is not suitable for high‑frequency vibration.

Types of Accelerometers (Overview)

We now examine several implementation types, all using the same basic mass–spring concept but with different displacement sensing:

  1. Potentiometric
  2. LVDT‑based
  3. Variable reluctance
  4. Piezoelectric

Each has characteristic range, natural frequency, and output type.

Potentiometric Accelerometers

  • Spring‑mass system with the mass connected to the wiper of a potentiometer.
  • Mass motion → wiper motion → resistance change.
  • Requires excitation (voltage) + signal‑conditioning to get a usable voltage or current output.
  • Typical:
    • Natural frequency \(< 30\ \mathrm{Hz}\)
    • Used for steady‑state or low‑frequency acceleration.

Note

Advantages: simple, low cost. Disadvantages: limited bandwidth, mechanical wear, not suited for harsh vibration.

LVDT‑Based Accelerometers

Use an LVDT (Linear Variable Differential Transformer) to measure mass displacement.

  • The LVDT core serves as the seismic mass.
  • Core motion → change in induced differential voltage → linear displacement signal.

LVDT accelerometer construction

Typical features:

  • Natural frequency \(\lesssim 80\ \mathrm{Hz}\)
  • Excellent linearity over range
  • Used for steady‑state and low‑frequency vibration measurements

Variable‑Reluctance Accelerometers

  • Rely on changing magnetic flux and induced voltage.
  • Test mass is a permanent magnet.
  • As the magnet moves within a coil, it induces a voltage.

Key traits:

  • Output only when the mass is moving (no DC/static acceleration).
  • Used mainly for vibration and shock.
  • Natural frequency typically \(\lesssim 100\ \mathrm{Hz}\).
  • Common application: geophones in oil exploration (measuring ground vibration).

Important

These are dynamic‑only sensors: no output for constant acceleration (e.g., constant tilt).

Piezoelectric Accelerometers

Use the piezoelectric effect: a crystal generates a voltage when mechanically stressed.

  • Test mass presses on a piezoelectric crystal.
  • Acceleration → inertial force \(F = ma\) on mass → stress on crystal → voltage.

Piezoelectric accelerometer – high natural frequency

Features:

  • Very high natural frequency (often \(> 5\ \mathrm{kHz}\)).
  • Ideal for vibration and shock measurements.
  • Output: small voltage (mV range), very high source impedance → needs a high‑impedance, low‑noise amplifier.
  • Cannot truly measure DC acceleration (behaves like a high‑pass system).

Application: Steady‑State Acceleration & Integration

For nonperiodic or slowly varying acceleration (e.g., vehicle motion, elevator):

Requirements:

  1. Sufficient range for expected accelerations.
  2. Natural frequency high enough that its period is shorter than time scale of acceleration changes.

Integration strategy:

  • Integrate acceleration to get velocity.
  • Integrate again to get position.

Using an integrator to get velocity from accelerometer

Example 15 – Integrator Design for Velocity

An accelerometer outputs \(14\ \mathrm{mV/g}\).

Design signal conditioning to produce a velocity signal scaled at \(0.25\ \mathrm{V}\) per \((\mathrm{m/s})\). Determine:

  • Overall gain factor
  • Feedback resistor ratio \(R_2/R_1\) in the final op‑amp stage

Solution outline

  1. Convert sensitivity to \(\mathrm{mV / (m/s^2)}\):

\[ K = 14\ \frac{\mathrm{mV}}{\mathbf{g}} \cdot \frac{1\ \mathbf{g}}{9.8\ \mathrm{m/s^2}} \approx 1.43\ \frac{\mathrm{mV}}{\mathrm{m/s^2}} \]

  1. Let \(V_a = K a\) be accelerometer output.
  1. Feed into op‑amp integrator:

\[ V_v = -\frac{1}{RC} \int V_a dt = -\frac{K}{RC} v \]

  1. Follow with inverting amplifier of gain \(R_2/R_1\) to flip sign and set scale:

\[ V_{\text{out}} = \left(\frac{R_2}{R_1}\right)\frac{K}{RC} v \]

We want \(V_{\text{out}} = 0.25 v\), so:

\[ 0.25 = \left(\frac{R_2}{R_1}\right)\frac{K}{RC} \]

Choose \(R = 1\ \mathrm{M\Omega}\), \(C = 1\ \mu\mathrm{F}\)\(RC = 1\).

Then:

\[ \frac{R_2}{R_1} = \frac{0.25}{1.43 \times 10^{-3}} \approx 175 \]

So one practical choice: \(R_1 = 1\ \mathrm{k\Omega}\), \(R_2 = 175\ \mathrm{k\Omega}\).

Accelerometer Selection Summary

  • Steady‑state / low‑frequency:
    • Potentiometric, LVDT‑based, capacitive (MEMS) accelerometers.
  • Vibration (10 Hz–several kHz):
    • Piezoelectric or high‑frequency MEMS devices.
  • Shock (\(>500\ \mathbf{g}\), \(\mathrm{kHz}\) bandwidth):
    • Piezoelectric accelerometers, specialized high‑g MEMS.

Key spec checklist:

  1. Range (max g)
  2. Bandwidth / natural frequency
  3. Ability to measure DC vs only AC
  4. Sensitivity and noise
  5. Environmental robustness (temperature, shock survival)

Pressure: Basic Concepts

Pressure = force per unit area exerted by a fluid (liquid or gas).

SI unit:

  • \(1\ \mathrm{Pa} = 1\ \mathrm{N/m^2}\)

Often use prefixes:

  • \(1\ \mathrm{kPa} = 10^3\ \mathrm{Pa}\)
  • \(1\ \mathrm{MPa} = 10^6\ \mathrm{Pa}\)

Other common units:

  • \(\mathrm{psi}\) (pounds per square inch)
    • \(1\ \mathrm{psi} \approx 6.895\ \mathrm{kPa}\)
  • torr (vacuum systems, low pressure)
    • \(1\ \mathrm{torr} \approx 133.3\ \mathrm{Pa}\)
  • atmosphere (atm): \(101.325\ \mathrm{kPa} \approx 14.7\ \mathrm{psi}\)
  • bar: \(1\ \mathrm{bar} = 100\ \mathrm{kPa}\)

Static vs Dynamic Pressure

  • Static pressure: fluid not moving relative to its container.
    • Example: water at rest in a vertical tank.
  • Dynamic pressure: pressure in a moving fluid depends on flow conditions.
    • Example: water in a hose; pressure changes when you open/close the nozzle.

Measurement systems must clearly state whether they are reading:

  • Static pressure only, or
  • Some combination of static + dynamic (e.g., Pitot tubes in airflow).

Gauge Pressure

Atmospheric pressure at sea level: ~\(14.7\ \mathrm{psi}\) (1 atm).

Often, we care about pressure relative to atmosphere, not absolute.

  • Absolute pressure \(p_{\text{abs}}\): measured from vacuum.
  • Gauge pressure \(p_g\): relative to ambient atmosphere.

Relationship:

\[ p_g = p_{\text{abs}} - p_{\text{at}} \tag{30} \]

  • In English units, use psig for gauge pressure.

Note

A sealed container at \(14.7\ \mathrm{psi}\) absolute, sitting at sea level, has \(p_g = 0\) (no net force on the walls).

Head Pressure (Hydrostatic Pressure)

For a liquid column of depth \(h\):

SI form:

\[ p = \rho g h \tag{31} \]

Where:

  • \(p\) = pressure (Pa)
  • \(\rho\) = mass density \((\mathrm{kg/m^3})\)
  • \(g \approx 9.8\ \mathrm{m/s^2}\)
  • \(h\) = depth (m)

English form using weight density \(\rho_w\) \((\mathrm{lb/ft^3})\):

\[ p = \rho_w h \tag{32} \]

Where \(p\) is in \(\mathrm{lb/ft^2}\).

To get psi, divide by 144 (since \(1\ \mathrm{ft^2} = 144\ \mathrm{in^2}\)).

Tip

“Feet (or meters) of water” is a pressure unit: it’s shorthand for the pressure produced by that water column height.

Example 16 – Tank Bottom Pressure

A tank holds water with depth \(7.0\ \mathrm{ft}\).

Find the pressure at the bottom in:

  1. Pa
  2. psi

Given: water density \(\rho = 10^3\ \mathrm{kg/m^3}\).

Solution

Convert depth:

\[ h = 7.0\ \mathrm{ft} = 7.0 \cdot 0.3048\ \mathrm{m/ft} \approx 2.1\ \mathrm{m} \]

Use Equation (31):

\[ p = \rho g h = (10^3)(9.8)(2.1) \approx 2.1 \times 10^4\ \mathrm{Pa} = 21\ \mathrm{kPa} \]

To express in psi, we can use \(\rho_w \approx 62.4\ \mathrm{lb/ft^3}\).

Pressure in \(\mathrm{lb/ft^2}\):

\[ p = \rho_w h = (62.4\ \mathrm{lb/ft^3})(7.0\ \mathrm{ft}) = 437\ \mathrm{lb/ft^2} \]

Convert to psi:

\[ p = \frac{437}{144}\ \mathrm{psi} \approx 3\ \mathrm{psi} \]

Pressure‑to‑Displacement Elements

Most industrial pressure sensors first convert pressure → displacement, then measure displacement electrically.

Common mechanical elements:

  1. Diaphragm
  2. Bellows
  3. Bourdon tube

Then convert displacement with:

  • Potentiometers
  • LVDTs
  • Strain gauges
  • Capacitive sensors

diaphragm bellow bourdon spiral bourdon

Diaphragm Pressure Element

A thin flexible metal diaphragm with pressures \(p_1\) and \(p_2\) on each side.

Net force:

\[ F = (p_2 - p_1) A \tag{33} \]

Where \(A\) is diaphragm area.

Diaphragm with differential pressure
  • Diaphragm deflects until Hooke’s law force balances pressure force.
  • Deflection (displacement) is proportional to pressure difference.

Bellows & LVDT Combination Pressure Element

Bellows: an accordion‑like metal structure.

  • Pressure difference causes straight‑line expansion or contraction.
  • Displacement is nearly linear with \(\Delta p\).

Bellows with LVDT displacement sensor
  • An LVDT measures bellows tip displacement.
  • Output voltage then becomes a linear function of pressure.

Bourdon Tube Pressure Element

Probably the most common mechanical pressure‑to‑displacement element.

Construction:

  1. Start with a hard metal tube (e.g., brass), flatten its cross‑section.
  2. Bend into a curved arc or spiral.
  3. Seal one end, connect other end to pressure source.

Bourdon tube fabrication and operation

Operation:

  • If internal pressure > external pressure, tube tends to straighten.
  • If internal pressure < external, tube tends to curl more.
  • Tip motion is proportional to pressure difference.

Most analog round‑dial pressure gauges use a Bourdon tube driving a pointer via gears.

Electronic Pressure Conversion

Once we have displacement, we can convert to an electrical signal using:

  • Potentiometers – measure displacement as resistance.
  • Strain gauges – often bonded directly to diaphragms.
  • Inductive sensors – LVDTs, variable reluctance arrangements.
  • Capacitive sensors – especially in MEMS devices.

Advanced differential pressure cell with feedback:

Differential pressure cell with feedback
  • A diaphragm senses \(\Delta p = p_1 - p_2\).
  • A feedback actuator (e.g., induction motor) keeps diaphragm nearly centered.
  • Drive signal needed to null deflection becomes the pressure measurement.

Solid‑State (Silicon) Pressure Sensors

Integrated‑circuit technology enables compact solid‑state (SS) pressure sensors.

Solid-state pressure sensor package

Inside:

Internal structure with silicon diaphragm and strain gauges
  • A thin silicon diaphragm deflects under pressure.
  • Semiconductor strain gauges are diffused directly into the silicon.
  • On‑chip signal conditioning: amplification, temperature compensation, linearization.

Configurations:

  • Gauge: one side open to atmosphere.
  • Absolute: one side sealed and evacuated.
  • Differential: both sides connected to two different pressures.

Absolute and differential SS pressure sensors

Solid‑State Pressure Sensor Specs

Typical characteristics:

  1. Sensitivity: 10–100 mV/kPa.
  2. Response time: around 10 ms (10–90% step response).
    • Not truly first‑order; vendor defines its own response time spec.
  3. Output: approximately linear voltage vs pressure over the operating range.
  4. Interface: often just three wires:
    • Supply (e.g., +5 V)
    • Ground
    • Output (analog voltage)

Applications:

  • Low‑pressure process control (0–100 kPa range).
  • Level sensing via head pressure.
  • Consumer products: washing machines, dishwashers, HVAC.

Example 17 – Level Measurement with SS Pressure Sensor

A SS pressure sensor outputs \(25\ \mathrm{mV/kPa}\) over 0–25 kPa.

We measure the level of a liquid with density \(\rho = 1.3 \times 10^3\ \mathrm{kg/m^3}\) by mounting the sensor at the tank bottom.

Find:

  1. Output voltage for levels from 0 to \(2.0\ \mathrm{m}\).
  2. Sensitivity in \(\mathrm{mV/cm}\) of level.

Solution

At height \(h\):

\[ p = \rho g h = (1.3 \times 10^3)(9.8)(h) \]

For \(h = 2.0\ \mathrm{m}\):

\[ p = 1.3 \times 10^3 \cdot 9.8 \cdot 2.0 \approx 25.48\ \mathrm{kPa} \]

Sensor output:

\[ V = (25\ \mathrm{mV/kPa})(25.48\ \mathrm{kPa}) \approx 637\ \mathrm{mV} = 0.637\ \mathrm{V} \]

So, for 0–2.0 m: 0–0.637 V.

Sensitivity per cm (200 cm range):

\[ S = \frac{637\ \mathrm{mV}}{200\ \mathrm{cm}} \approx 3.19\ \mathrm{mV/cm} \]

Very Low Pressure (Vacuum) Sensors

For \(p < 1\) atm, down to about \(10^{-3}\) atm, two heat‑based methods:

  1. Pirani gauge
    • Measures filament temperature via resistance in a bridge circuit.
    • Heat loss ∝ number of gas molecules → pressure.
    • Highly nonlinear, gas‑type dependent.
  2. Thermocouple gauge
    • Measures filament temperature with a thermocouple attached to the filament.
    • Output voltage ∝ temperature ∝ pressure (nonlinear).

For even lower pressures (\(10^{-3}\) to \(10^{-13}\) atm):

  1. Ionization gauge

Ionization gauge principle
  • Electrons from a heated filament ionize gas molecules.
  • Current between electrodes ∝ ion density ∝ pressure.

Summary / Key Points

  • Motion sensing starts from \(x(t)\), \(v(t)\), \(a(t)\) relationships: accelerometers measure acceleration, which can be integrated to get velocity and position.
  • Types of motion: rectilinear, angular, vibration, and shock. Each calls for different sensor ranges and bandwidths.
  • The spring–mass accelerometer uses \(F = ma\) and \(F = k\Delta x\)\(a = (k/m)\Delta x\).
  • Natural frequency and damping determine how an accelerometer responds to vibration.
    • Avoid using near resonance (\(f \approx f_N\)).
  • Accelerometer types:
    • Potentiometric and LVDT: good for steady or low‑frequency motion.
    • Variable‑reluctance: dynamic (vibration/shock) only.
    • Piezoelectric: high‑frequency vibration and shock; no DC.
  • Pressure is force per unit area, usually measured in Pa, psi, or related units.
    • Gauge pressure: \(p_g = p_{\text{abs}} - p_{\text{at}}\).
    • Hydrostatic head: \(p = \rho g h\).
  • Common pressure elements: diaphragm, bellows, Bourdon tube.
    • Displacement → potentiometer, LVDT, strain gauge, etc.
  • Solid‑state pressure sensors use silicon diaphragms with on‑chip strain gauges and conditioning, offering simple voltage outputs for 0–100 kPa ranges.

Formula Summary

Kinematics & Vibration

  • Velocity from position: \[v(t) = \frac{dx(t)}{dt} \tag{16}\]

  • Acceleration from velocity/position: \[a(t) = \frac{dv(t)}{dt} = \frac{d^2 x(t)}{dt^2} \tag{17}\]

  • Velocity from acceleration (integral): \[v(t) = v(0) + \int_0^t a(\tau)\, d\tau \tag{18}\]

  • Position from velocity (integral): \[x(t) = x(0) + \int_0^t v(\tau)\, d\tau \tag{19}\]

  • Sinusoidal vibration: \[x(t) = x_0 \sin(\omega t) \tag{20}\]

  • Angular frequency–frequency relation: \[\omega = 2\pi f \tag{21}\]

  • Vibration velocity: \[v(t) = \omega x_0 \cos(\omega t) \tag{22}\]

  • Vibration acceleration: \[a(t) = -\omega^2 x_0 \sin(\omega t) \tag{23}\]

  • Peak acceleration: \[a_{\text{peak}} = \omega^2 x_0 \tag{24}\]

Formula Summary (cont.)

Accelerometer & Dynamics

  • Spring–mass equilibrium: \[ma = k\Delta x \tag{25}\]

  • Acceleration–displacement relation: \[a = \frac{k}{m}\Delta x \tag{26}\]

  • Natural frequency (Hz): \[f_N = \frac{1}{2\pi}\sqrt{\frac{k}{m}} \tag{27}\]

  • Damped transient response: \[X_T(t) = X_0 e^{-\alpha t}\sin(2\pi f_N t) \tag{28}\]

  • Mass motion under vibration (simplified): \[\Delta x = -\frac{m x_0}{k}\omega^2 \sin(\omega t) \tag{29}\]

Pressure & Head

  • Gauge pressure: \[p_g = p_{\text{abs}} - p_{\text{at}} \tag{30}\]

  • Hydrostatic pressure (SI): \[p = \rho g h \tag{31}\]

  • Hydrostatic pressure (English, weight density): \[p = \rho_w h \tag{32}\]

  • Diaphragm force: \[F = (p_2 - p_1)A \tag{33}\]

Motion & Pressure Sensors – Interactive Deck

Warm‑Up: Unit Conversion (Acceleration)

Use Pyodide to convert acceleration from ft/s² to m/s² and g.

Explore Vibration: \(x(t)\), \(v(t)\), \(a(t)\)

Visualize sinusoidal vibration position, velocity, and acceleration.

Reactive Vibration Explorer

Use sliders to control frequency and peak displacement, then see the vibration responses.

Important

Notice how small changes in \(f\) have a big effect on peak acceleration because \(a_{\text{peak}} = \omega^2 x_0\).

Peak Acceleration vs Frequency

Plot \(a_{\text{peak}} = \omega^2 x_0\) as a function of frequency for different \(x_0\).

Spring–Mass Accelerometer: Natural Frequency

Experiment with \(m\), \(k\) and see how natural frequency changes.

Reactive Spring–Mass Designer

Adjust \(m\) and \(k\) via sliders and see \(f_N\) plus a suggested usable bandwidth.

Tip

As a rule of thumb, use an accelerometer up to roughly \(f_N / 2.5\) for accurate acceleration measurements.

Shock Example: Drop Test Simulator

Simulate average deceleration from a drop of height \(h\) with shock duration \(T_d\).

Reactive Shock Explorer

Use sliders for drop height and shock duration; plot average g as a function of \(h\).

Pressure: Unit Conversion Playground

Practice converting between Pa, kPa, psi, and atm.

Hydrostatic Pressure vs Depth

Use sliders to explore \(p = \rho g h\) for different depths and fluid densities.

Level‑to‑Voltage Mapping (SS Pressure Sensor)

Simulate Example 17: level measurement using a SS pressure sensor.

Reactive Level Sensor Simulator

Interactively see how tank level maps to pressure and sensor output voltage.

Reflection: What Did You Observe?

Use your experiments to answer:

  1. How does vibration frequency vs amplitude affect peak acceleration?
  2. How do mass and spring constant change the natural frequency of an accelerometer?
  3. How does hydrostatic pressure scale with depth and density?
  4. How does a pressure sensor’s sensitivity (mV/kPa) translate into a level sensitivity (mV/cm)?

Note

Capture these observations—they form the basis of lab reports and exam solutions.